Impulse...?

Aug 31, 2007 by galofdasouth | Posted in Physics

A proton has a mass of 1.7 10-27 kg. What is the magnitude of the impetus in the direction of movement to increase speed of 0.991c to 0.994c?

The answer should have units of N * S
The answer I got is 1.53E-21. People have two answers are both calculation errors. The first speed is 991 not 99. And there is no way that it equals 0. Check the math.

But WebAssign keeps telling me I'm wrong.

Impulse = Ft = change in momentum = m [VU]

Pulse = 1.7 x 10 ^ (-27) ([0.994 to 0.99] c)

Pulse = 1.7 x 10 ^ (-27) * (0,004 x 3 x 10 ^ 8) = 2.04e-21 ns.
=============================================
Since the particle moves at a speed comparable to the speed of C, you must apply the formula to find the relativistic momentum.
Pulse = 2.04e-21 / [1 0.99 ^ 2] ^ 3 / 2 = 7.3 x 10 ^ [-19] Ns.

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